125^x=(1/5)^2x-15

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Solution for 125^x=(1/5)^2x-15 equation: 



125^x=(1/5)^2x-15

We move all terms to the left:

125^x-((1/5)^2x-15)=0



Domain of the equation: 5)^2x-15)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

125^x-((+1/5)^2x-15)=0

We multiply all the terms by the denominator


125^x*5)^2x-15)-((+1=0

Wy multiply elements

625x^2+1=0

a = 625; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·625·1
Δ = -2500
Delta is less than zero, so there is no solution for the equation

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